3m^2-26m-3=0

Solution for 3m^2-26m-3=0 equation:

3m^2-26m-3=0

a = 3; b = -26; c = -3;
Δ = b2-4ac
Δ = -262-4·3·(-3)
Δ = 712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{712}=\sqrt{4*178}=\sqrt{4}*\sqrt{178}=2\sqrt{178}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{178}}{2*3}=\frac{26-2\sqrt{178}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{178}}{2*3}=\frac{26+2\sqrt{178}}{6}
$